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###################

Mavjud bo'lmagan indeks yoki kalitlarni tekshirish uchun umumiy LookupError dan yoki LookupError dan meros bo'lib olingan IndexError, KeyError dan foydalanishingiz mumkin.

x = [1, 2, 3, 4, 5]
try:
print(x[5])
except LookupError as e:
print(f"{e}, {e.class}")

list index out of range, <class 'IndexError'>

# ——————————————-#

lugat = {1: 'one', 2: 'two'}
try:
print(lugat[3])
except LookupError as e:
print(f'{e}, {e.class}')

3, <class 'KeyError'>

###################

Dastur operatsion tizim xotirasidan katta hajmdagi xotirani iste'mol qilganda MemoryError xatoligi paydo bo'ladi.

import numpy
try:
numpy.ones((9999999999,))
except MemoryError as e:
print(e)

Unable to allocate 74.5 GiB for an array with shape (9999999999,) and data type float64
###################

Noto'g'ri yozilgan funksiya nomi yozilganda dastur NameError xatoligini qaytaradi.

try:
prin('Hello')
except NameError as e:
print(e, e.class)

name 'prin' is not defined <class 'NameError'>

# ——————————————-#
Mavjud bo'lmagan o'zgaruvchi yozilganda dastur NameError xatoligini qaytaradi.

try:
var = 42
print(war)
except NameError as e:
print(e, e.class)

name 'war' is not defined <class 'NameError'>

# ——————————————-#
O'zgaruvchisi biror tur/qiymatga ega bo'lmagan funksiyaga murojaat qilinganda dastur UnboundLocalError xatoligini qaytaradi.

def func():
x += 1
print(x)


func()

UnboundLocalError: local variable 'x' referenced before assignment

###################

Dastur ishga tushirilganda dasturlash tili qoidalariga amal qilinmaganda (sintaksis xatolar bo'lsa) SyntaxError xatoligini qaytaradi.Keraksiz joyda nuqta, vergul, bo'sh joy, operator yoki funksiyalar nomini xato yozish, ochilmay yoki yopilmay qolgan qavs, ikkitirnoq yoki birtirnoqlar, o'zgaruvchilarga noto'g'ri nom berish SyntaxError ga misol bo'la oladi.

len() = 5

SyntaxError: cannot assign to function call

# ——————————————-#

fro i in range(10):
print(i)

SyntaxError: invalid syntax

# ——————————————-#

Kod bloklarida noto'g'ri yozilgan bo'sh joylar IndentationError xatoligini qaytaradi.

num = 5
if num == 5:
print('ok')

IndentationError: expected an indented block

# ——————————————-#

Yorliqlar va bo'shliqlardan noto'g'ri foydalanganda dastur TabError xatoligini qaytaradi

rating_range = 1
for row in range(6):
if 200 <= 199:
rating_range += 1
print(rating_range)

TabError: inconsistent use of tabs and spaces in indentation

###################

Noto'g'ri ma'lumot turlari ustida amallar bajarilganda dastur TypeError xatoligini qaytaradi.
Quyidagi holatlarda dastur TypeError xatoligini qaytaradi.

——————————————-#

Matn va sonni birlashtirishga uringanda

num  = 42
matn = '-maktab'
print(num + matn)

TypeError: unsupported operand type(s) for +: 'int' and 'str'

——————————————-#

O'zgaruvchini funksiya ko'rinishida chaqirganda

var = 'pythonuz'
print(var())

TypeError: 'str' object is not callable

——————————————-#

Ro'yxat indeksida noto'g'ri ma'lumot turi ko'rsatilganda

royxat = ['pythonuz', 'phpuz']
print(royxat['1'])

TypeError: list indices must be integers or slices, not str

###############

Biror amal yoki funktsiya mos bo'lmagan qiymatga ega bo'lgan argumentni qabul qilganda dastur ValueError xatoligini qaytaradi.

import math
x = -9
try:
print(f'{x} ning kvadrat ildizi {math.sqrt(x)}')
except ValueError as e:
print({e}, {e.class})

{ValueError('math domain error')} {<class 'ValueError'>}

——————————————-#

try:
int('two')
except ValueError as e:
print({e}, {e.class})


{ValueError("invalid literal for int() with base 10: 'two'")} {<class 'ValueError'>}

###############

Python dasturlash tiliga oid savollarni ushbu guruhga yozing @apiuz



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Boshiga https://www.tg-me.com/ar/Python dasturlash maktabi/com.pythonuz/590

###################

Mavjud bo'lmagan indeks yoki kalitlarni tekshirish uchun umumiy LookupError dan yoki LookupError dan meros bo'lib olingan IndexError, KeyError dan foydalanishingiz mumkin.

x = [1, 2, 3, 4, 5]
try:
print(x[5])
except LookupError as e:
print(f"{e}, {e.class}")

list index out of range, <class 'IndexError'>

# ——————————————-#

lugat = {1: 'one', 2: 'two'}
try:
print(lugat[3])
except LookupError as e:
print(f'{e}, {e.class}')

3, <class 'KeyError'>

###################

Dastur operatsion tizim xotirasidan katta hajmdagi xotirani iste'mol qilganda MemoryError xatoligi paydo bo'ladi.

import numpy
try:
numpy.ones((9999999999,))
except MemoryError as e:
print(e)

Unable to allocate 74.5 GiB for an array with shape (9999999999,) and data type float64
###################

Noto'g'ri yozilgan funksiya nomi yozilganda dastur NameError xatoligini qaytaradi.

try:
prin('Hello')
except NameError as e:
print(e, e.class)

name 'prin' is not defined <class 'NameError'>

# ——————————————-#
Mavjud bo'lmagan o'zgaruvchi yozilganda dastur NameError xatoligini qaytaradi.

try:
var = 42
print(war)
except NameError as e:
print(e, e.class)

name 'war' is not defined <class 'NameError'>

# ——————————————-#
O'zgaruvchisi biror tur/qiymatga ega bo'lmagan funksiyaga murojaat qilinganda dastur UnboundLocalError xatoligini qaytaradi.

def func():
x += 1
print(x)


func()

UnboundLocalError: local variable 'x' referenced before assignment

###################

Dastur ishga tushirilganda dasturlash tili qoidalariga amal qilinmaganda (sintaksis xatolar bo'lsa) SyntaxError xatoligini qaytaradi.Keraksiz joyda nuqta, vergul, bo'sh joy, operator yoki funksiyalar nomini xato yozish, ochilmay yoki yopilmay qolgan qavs, ikkitirnoq yoki birtirnoqlar, o'zgaruvchilarga noto'g'ri nom berish SyntaxError ga misol bo'la oladi.

len() = 5

SyntaxError: cannot assign to function call

# ——————————————-#

fro i in range(10):
print(i)

SyntaxError: invalid syntax

# ——————————————-#

Kod bloklarida noto'g'ri yozilgan bo'sh joylar IndentationError xatoligini qaytaradi.

num = 5
if num == 5:
print('ok')

IndentationError: expected an indented block

# ——————————————-#

Yorliqlar va bo'shliqlardan noto'g'ri foydalanganda dastur TabError xatoligini qaytaradi

rating_range = 1
for row in range(6):
if 200 <= 199:
rating_range += 1
print(rating_range)

TabError: inconsistent use of tabs and spaces in indentation

###################

Noto'g'ri ma'lumot turlari ustida amallar bajarilganda dastur TypeError xatoligini qaytaradi.
Quyidagi holatlarda dastur TypeError xatoligini qaytaradi.

——————————————-#

Matn va sonni birlashtirishga uringanda

num  = 42
matn = '-maktab'
print(num + matn)

TypeError: unsupported operand type(s) for +: 'int' and 'str'

——————————————-#

O'zgaruvchini funksiya ko'rinishida chaqirganda

var = 'pythonuz'
print(var())

TypeError: 'str' object is not callable

——————————————-#

Ro'yxat indeksida noto'g'ri ma'lumot turi ko'rsatilganda

royxat = ['pythonuz', 'phpuz']
print(royxat['1'])

TypeError: list indices must be integers or slices, not str

###############

Biror amal yoki funktsiya mos bo'lmagan qiymatga ega bo'lgan argumentni qabul qilganda dastur ValueError xatoligini qaytaradi.

import math
x = -9
try:
print(f'{x} ning kvadrat ildizi {math.sqrt(x)}')
except ValueError as e:
print({e}, {e.class})

{ValueError('math domain error')} {<class 'ValueError'>}

——————————————-#

try:
int('two')
except ValueError as e:
print({e}, {e.class})


{ValueError("invalid literal for int() with base 10: 'two'")} {<class 'ValueError'>}

###############

Python dasturlash tiliga oid savollarni ushbu guruhga yozing @apiuz

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Spiking bond yields driving sharp losses in tech stocks

A spike in interest rates since the start of the year has accelerated a rotation out of high-growth technology stocks and into value stocks poised to benefit from a reopening of the economy. The Nasdaq has fallen more than 10% over the past month as the Dow has soared to record highs, with a spike in the 10-year US Treasury yield acting as the main catalyst. It recently surged to a cycle high of more than 1.60% after starting the year below 1%. But according to Jim Paulsen, the Leuthold Group's chief investment strategist, rising interest rates do not represent a long-term threat to the stock market. Paulsen expects the 10-year yield to cross 2% by the end of the year. A spike in interest rates and its impact on the stock market depends on the economic backdrop, according to Paulsen. Rising interest rates amid a strengthening economy "may prove no challenge at all for stocks," Paulsen said.

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